Golang execute go routine in a loop

Does the following code output “Sum = 45”? The answer is NO.

package main
import (
   "fmt"
   "sync"
)
func ConcurrentSum(l int) int {
   var wg sync.WaitGroup
   c := make(chan int, l)
   for i := 0; i < l; i++ {
      wg.Add(1)
      go func() {
         c <- i
         wg.Done()
      }()
    }
    wg.Wait()
    close(c)
 
    return processResult(c)
}
func processResult(c <-chan int) int {
    total := 0
    for n := range c {
        total += n
    }
    return total
}
func main() {
    sum := ConcurrentSum(10);
    //What is the output here?
    fmt.Println("Sum = ", sum)
}

If you want to have an output of “Sum = 45”, you have to pass the loop variable into the go routine as a parameter as below.

package main
import (
   "fmt"
   "sync"
)
func ConcurrentSum(l int) int {
   var wg sync.WaitGroup
   c := make(chan int, l)
   for i := 0; i < l; i++ {
       wg.Add(1)
       go func(n int) {
          c <- n
          wg.Done()
       }(i)
    }
    wg.Wait()
    close(c)
 
    return processResult(c)
}
func processResult(c <-chan int) int {
    total := 0
    for n := range c {
        total += n
    }
    return total
}
func main() {
    sum := ConcurrentSum(10);
    //Output: Sum =  45
    fmt.Println("Sum = ", sum)
}